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Exam Code: 312-49
Exam Name: EC-COUNCIL (Computer Hacking Forensic Investigator )
One year free update, No help, Full refund!
Total Q&A: 150 Questions and Answers
Last Update: 2014-02-09

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NO.1 How many characters long is the fixed-length MD5 algorithm checksum of a critical system file?
A. 128
B. 64
C. 32
D. 16
Answer: C

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NO.2 When an investigator contacts by telephone the domain administrator or controller listed by a
whois lookup to request all e-mails sent and received for a user account be preserved, what
U.S.C. statute authorizes this phone call and obligates the ISP to preserve e-mail records?
A. Title 18, Section 1030
B. Title 18, Section 2703(d)
C. Title 18, Section Chapter 90
D. Title 18, Section 2703(f)
Answer: D

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NO.3 You are contracted to work as a computer forensics investigator for a regional bank that has four
30 TB storage area networks that store customer data. What method would be most efficient for
you to acquire digital evidence from this network?
A. create a compressed copy of the file with DoubleSpace
B. create a sparse data copy of a folder or file
C. make a bit-stream disk-to-image fileC
D. make a bit-stream disk-to-disk file
Answer: C

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NO.4 The offset in a hexadecimal code is:
A. The last byte after the colon
B. The 0x at the beginning of the code
C. The 0x at the end of the code
D. The first byte after the colon
Answer: B

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NO.5 What does the superblock in Linux define?
A. file system names
B. available space
C. location of the first inode
D. disk geometry
Answer: B, C, D

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NO.6 When examining a file with a Hex Editor, what space does the file header occupy?
A. the last several bytes of the file
B. the first several bytes of the file
C. none, file headers are contained in the FAT
D. one byte at the beginning of the file
Answer: D

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NO.7 What file structure database would you expect to find on floppy disks?
A. NTFS
B. FAT32
C. FAT16
D. FAT12
Answer: D

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NO.8 It takes _____________ mismanaged case/s to ruin your professional reputation as a computer
forensics examiner?
A. by law, three
B. quite a few
C. only one
D. at least two
Answer: C

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NO.9 When examining the log files from a Windows IIS Web Server, how often is a new log file
created?
A. the same log is used at all times
B. a new log file is created everyday
C. a new log file is created each week
D. a new log is created each time the Web Server is started
Answer: A

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NO.10 In a computer forensics investigation, what describes the route that evidence takes from the time
you find it until the case is closed or goes to court?
A. rules of evidence
B. law of probability
C. chain of custody
D. policy of separation
Answer: C

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NO.11 Before you are called to testify as an expert, what must an attorney do first?
A. engage in damage control
B. prove that the tools you used to conduct your examination are perfect
C. read your curriculum vitae to the jury
D. qualify you as an expert witness
Answer: D

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NO.12 If you come across a sheepdip machine at your client site, what would you infer?
A. A sheepdip coordinates several honeypots
B. A sheepdip computer is another name for a honeypot
C. A sheepdip computer is used only for virus-checking.
D. A sheepdip computer defers a denial of service attack
Answer: C

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NO.13 A honey pot deployed with the IP 172.16.1.108 was compromised by an attacker . Given below is
an excerpt from a Snort binary capture of the attack. Decipher the activity carried out by the
attacker by studying the log. Please note that you are required to infer only what is explicit in the
excerpt. (Note: The student is being tested on concepts learnt during passive OS fingerprinting,
basic TCP/IP connection concepts and the ability to read packet signatures from a sniff dump.)
03/15-20:21:24.107053 211.185.125.124:3500 -> 172.16.1.108:111
TCP TTL:43 TOS:0x0 ID:29726 IpLen:20 DgmLen:52 DF
***A**** Seq: 0x9B6338C5 Ack: 0x5820ADD0 Win: 0x7D78 TcpLen: 32
TCP Options (3) => NOP NOP TS: 23678634 2878772
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.452051 211.185.125.124:789 -> 172.16.1.103:111
UDP TTL:43 TOS:0x0 ID:29733 IpLen:20 DgmLen:84
Len: 64
01 0A 8A 0A 00 00 00 00 00 00 00 02 00 01 86 A0 ................
00 00 00 02 00 00 00 03 00 00 00 00 00 00 00 00 ................
00 00 00 00 00 00 00 00 00 01 86 B8 00 00 00 01 ................
00 00 00 11 00 00 00 00 ........
=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=+=
03/15-20:21:24.730436 211.185.125.124:790 -> 172.16.1.103:32773
UDP TTL:43 TOS:0x0 ID:29781 IpLen:20 DgmLen:1104
Len: 1084
47 F7 9F 63 00 00 00 00 00 00 00 02 00 01 86 B8 G..c............
00 00 00 01 00 00 00 01 00 00 00 01 00 00 00 20 ...............
3A B1 5E E5 00 00 00 09 6C 6F 63 61 6C 68 6F 73 :.